In parallelogram ABCD, the diagonals AC and BD intersect at O. Which one of the following gives a correct set of equalities that can be used to prove △AOB≅△COD by SAS?
(a) AO=CO,BO=DO,∠ABO=∠CDO
(b) AO=BO,CO=DO,∠AOB=∠COD
(c) AO=CO,BO=DO,∠AOB=∠COD
(d) AO=CO,AB=CD,∠AOB=∠COD