The reduction of occurs as NO _3^- + 4 H ^+ + 3e^- NO + 2 H _2 O ; E^ = 0.96 V The…

CHEMISTRY · Single correct · A Level · Chemistry · Electrode potentials · Electrode potentials

Problem

The reduction of NO3−\text{NO}_3^- occurs as NO3−+4H++3e−⟶NO+2H2O;E∘=0.96 V\text{NO}_3^- + 4\text{H}^+ + 3e^- \longrightarrow \text{NO} + 2\text{H}_2\text{O}; \quad E^\circ = 0.96 \text{ V} The electrons are provided by Cd till that the solution originally having 0.1 M NO3−\text{NO}_3^- and 0.4 M H+\text{H}^+ shows that 80% of NO3−\text{NO}_3^- ions are converted to NO showing 1 bar pressure. The reduction potential of remaining solution. (1) 0.84 V (2) 1.36 V (3) 1.08 V (4) 1.56 V

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