Let h(x)= cases kx^ 2 , & x<0

MATHEMATICS · Single correct · AP · Calculus AB · Differentiation: Definition and Fundamental Properties · Differentiation: Definition and Fundamental Properties

Problem

Let h(x)={kx2,x<0,kx,x≥0,h(x)=\begin{cases} kx^{2}, & x<0,\\ kx, & x\ge 0, \end{cases} where k≠0k\neq 0 is a constant. Which statement about the differentiability of hh at x=0x=0 is correct? (a) hh is differentiable at x=0x=0 for every nonzero kk because both one-sided derivatives are 00. (b) hh is not differentiable at x=0x=0 for any nonzero kk because the left-hand derivative is 00 while the right-hand derivative is kk. (c) hh is differentiable at x=0x=0 only when k=1k=1. (d) hh is differentiable at x=0x=0 for every nonzero kk because both pieces are polynomials and therefore smooth.

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