The function has the Maclaurin series for

MATHEMATICS · Multi-part · AP · Calculus BC · Infinite Sequences and Series · Infinite Sequences and Series

Problem

The function g(x)=ln⁡(1+x)g(x)=\ln(1+x) has the Maclaurin series ∑n=1∞(−1)n+1xnn\displaystyle\sum_{n=1}^{\infty}(-1)^{n+1}\dfrac{x^{n}}{n} for −1<x≤1-1<x\le 1. You wish to approximate g(0.6)g(0.6) using a Taylor polynomial of degree NN. (a) Express the remainder RN(0.6)=g(0.6)−PN(0.6)R_{N}(0.6)=g(0.6)-P_{N}(0.6) in terms of an integral involving g(N+1)(c)g^{(N+1)}(c) for some cc between 00 and 0.60.6. No evaluation is required. (b) Obtain a numerical bound on ∣RN(0.6)∣|R_{N}(0.6)| that comes from the alternating character of the series. Your bound should be written explicitly in terms of NN. (c) Derive a second numerical bound on ∣RN(0.6)∣|R_{N}(0.6)| that relies on a maximum value of ∣g(N+1)(x)∣|g^{(N+1)}(x)| on [0,0.6][0,0.6]. Express the bound in closed form in terms of NN. (d) Determine the smallest integer NN for which both bounds ensure that ∣RN(0.6)∣<1×10−4|R_{N}(0.6)|<1\times10^{-4}. State which of the two bounds gives the more efficient guarantee and explain your reasoning.

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