For the reaction at 50°C the rate expression is given as : what percentage of RX…

CHEMISTRY · Single correct · A Level · Chemistry · Rate equations · Rate equations

Problem

For the reaction RX+OH−⟶ROH+X−RX + OH^- \longrightarrow ROH + X^- at 50°C the rate expression is given as : rate=4.7×10−5[RX][OH−]+0.24×10−5[RX]\text{rate} = 4.7 \times 10^{-5} [RX][OH^-] + 0.24 \times 10^{-5} [RX] what percentage of *RX* reacts by the *S_N2* mechanism when [OH−]=0.001M[OH^-] = 0.001 M (1) 0.192 (2) 0.0192 (3) 19.2 (4) 1.92

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