The position of a particle moving along a line is given by meters for

MATHEMATICS · Single correct · CBSE · Mathematics · Applications of Derivatives · Applications of Derivatives

Problem

The position of a particle moving along a line is given by s(t)=2t3−15t2+36ts(t)=2t^{3}-15t^{2}+36t meters for 0≤t≤40\le t\le4. At what time during this interval is the particle farthest to the right? (a) t=2.5t=2.5 (b) t=3t=3 (c) t=4t=4 (d) t=2t=2

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