Column I gives physical quantities of a situation in which a current passes through…

PHYSICS · Subjective · CBSE · Physics · Current Electricity · Current Electricity

Problem

Column I gives physical quantities of a situation in which a current

i

passes through two rods I and II of equal length that are joined in series. The ratio of free electron density (

n

), resistivity (

P

) and cross-section area (

A

) of both are in ratio

n_1 : n_2 = 2 : 1

P_1 : P_2 = 2 : 1

and

A_1 : A_2 = 1 : 2

respectively. Column II gives corresponding results. Match the ratios in column I with the values in Column II.

Column I	Column II
(a) $\frac{\text{Drift velocity of free electron in rod I}}{\text{Drift velocity of free electron in rod II}}$	(p) 0.5
(b) $\frac{\text{Electric field in rod I}}{\text{Electric field in rod II}}$	(q) 1
(c) $\frac{\text{Potential difference across rod I}}{\text{Potential difference across rod II}}$	(r) 2
(d) $\frac{\text{Average time taken by free electron to move across rod I}}{\text{Average time taken by free electron to move across rod II}}$	(s) 4