CBSE

MATHEMATICS · Single correct · CBSE · Mathematics · Inverse Trigonometric Functions · Inverse Trigonometric Functions

Problem

tan⁡(sec⁡−11+x2)=\tan\left(\sec^{-1}\sqrt{1+x^2}\right)= (a) 1x\frac{1}{x} (b) ∣x∣|x| (c) 11+x2\frac{1}{\sqrt{1+x^2}} (d) x1+x2\frac{x}{\sqrt{1+x^2}}

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