The triangle with vertices

MATHEMATICS · Single correct · CBSE · Mathematics · Coordinate Geometry · Coordinate Geometry

Problem

The triangle with vertices A(a,1)A(a,1), B(4,a)B(4,a) and C(2,5)C(2,5) has an area of 77 square units. If a>5a>5, find aa. (a) 3+53+\sqrt{5} (b) 7+412\dfrac{7+\sqrt{41}}{2} (c) 7+332\dfrac{7+\sqrt{33}}{2} (d) 7+172\dfrac{7+\sqrt{17}}{2}

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