For the function

MATHEMATICS · Single correct · AoPS · Mathematics · Special Functions · Special Functions

Problem

For the function p(x)=(x−4)2+∣x∣p(x)=(x-4)^2+|x|, the minimum value is attained at (a) x=4x=4 (b) x=92x=\dfrac{9}{2} (c) x=72x=\dfrac{7}{2} (d) x=2x=2

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