MATHEMATICS · Multi-part · AP · Calculus BC · Applications of Integration · Applications of Integration
Problem
For a fixed positive constant k, consider the curve y=k1cosh(kx) on the interval 0≤x≤b, where b>0.
(a) Show that 1+(dxdy)2=cosh(kx). Present a clear chain of equalities that leads to your conclusion.
(b) Derive a closed‐form expression for the arc length L(k,b) of the curve on [0,b] in terms of k and b. Express your final answer without an integral symbol.
(c) Evaluate L(2,ln3) exactly, where k=2 and b=ln3. Show all intermediate steps.
(d) Determine k→0+limL(k,b) for a fixed b>0 and interpret the limiting value in the context of the family of curves y=k1cosh(kx).