A parametrically defined curve satisfies the derivative values shown below

MATHEMATICS · Single correct · AP · Calculus BC · Parametric, Polar, and Vector-Valued Functions · Parametric, Polar, and Vector-Valued Functions

Problem

A parametrically defined curve satisfies the derivative values shown below. t=−2t=-2: x′(t)=0x'(t)=0, y′(t)=−3y'(t)=-3 t=0t=0: x′(t)=0x'(t)=0, y′(t)=0y'(t)=0 t=1t=1: x′(t)=2x'(t)=2, y′(t)=0y'(t)=0 t=3t=3: x′(t)=−1x'(t)=-1, y′(t)=4y'(t)=4 Which value of tt corresponds to a point where the curve has a vertical tangent? (a) t=1t=1 (b) t=−2t=-2 (c) t=3t=3 (d) t=0t=0

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