Hydrogen iodide is formed from its elements in the gas phase: H _2(g)+ I _2(g) 2 HI…

CHEMISTRY · Multi-part · A Level · Chemistry · Gaseous equilibria (Kp) · Gaseous equilibria (Kp)

Problem

Hydrogen iodide is formed from its elements in the gas phase: H2(g)+I2(g)⇌2HI(g)\text{H}_2(g)+\text{I}_2(g)\rightleftharpoons2\text{HI}(g) For this reaction ΔH∘=+51 kJ mol−1\Delta H^{\circ}= +51\,\text{kJ\,mol}^{-1} (per mole of reaction as written). The equilibrium constant in terms of pressure is Kp=54.3K_p = 54.3 at 700 K700\,\text{K}. A mixture at 900 K900\,\text{K} contains the following partial pressures: PH2=0.30 atmP_{\text{H}_2}=0.30\,\text{atm}, PI2=0.30 atmP_{\text{I}_2}=0.30\,\text{atm}, and PHI=1.20 atmP_{\text{HI}}=1.20\,\text{atm}. The universal gas constant is R=8.314 J mol−1K−1R = 8.314\,\text{J\,mol}^{-1}\text{K}^{-1}. (a) Calculate the numerical value of KpK_p at 900 K900\,\text{K}. (b) Determine the value of the reaction quotient QpQ_p for the given gas mixture at 900 K900\,\text{K}. (c) Indicate whether the forward reaction or the reverse reaction will be favored as the system moves toward equilibrium at 900 K900\,\text{K}. Support your answer with appropriate comparisons between QpQ_p and KpK_p.

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