An electron in a hydrogen atom falls from the fourth stationary orbit to the second…

CHEMISTRY · Multi-part · CBSE · Chemistry · Structure of Atom · Structure of Atom

Problem

An electron in a hydrogen atom falls from the fourth stationary orbit to the second stationary orbit and a photon is emitted. (Given: constant appearing in the hydrogen spectrum equation RH=1.097×107 m−1R_{H}=1.097\times10^{7}\,\text{m}^{-1}, Planck’s constant h=6.63×10−34 J sh=6.63\times10^{-34}\,\text{J\,s}, speed of light c=3.00×108 m s−1c=3.00\times10^{8}\,\text{m\,s}^{-1}, electronic charge e=1.60×10−19 Ce=1.60\times10^{-19}\,\text{C}) (i) Calculate the wavelength of the emitted photon. (ii) Determine its frequency. (iii) Find the energy of the photon in electron-volt.

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