Let A(x1,y1), B(x2,y2) and C(x3,y3) be the vertices of a triangle △ABC, and let P(xp,yp) be any point in the plane.
(a) Prove that
Area(PBC)+Area(PCA)+Area(PAB)=Area(ABC)
regardless of the position of P.
(b) Deduce from part (a) that, when P lies strictly inside △ABC, each of the ratios
Area(ABC)Area(PBC),Area(ABC)Area(PCA),Area(ABC)Area(PAB)
is positive and that their sum equals 1.
(c) If P lies on the side BC, identify which of the three ratios in part (b) becomes zero and verify that the sum of the ratios remains 1.