If the pair of straight lines be conjugate diameters of the hyperbola

MATHEMATICS · Subjective · CBSE · Mathematics · Conic Sections · Conic Sections

Problem

If the pair of straight lines Ax2+2Hxy+By2=0Ax^2 + 2Hxy + By^2 = 0 be conjugate diameters of the hyperbola x2a2−y2b2=1\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 , then prove that Aa2=Bb2Aa^2 = Bb^2 .

Related theory

Browse the problem library