The emf of the cell at is

CHEMISTRY · Single correct · A Level · Chemistry · Electrode potentials · Electrode potentials

Problem

The emf of the cell

\text{Zn} | \text{Zn}^{2+} (0.01 \text{ M}) || \text{Fe}^{2+} (0.001 \text{ M}) | \text{Fe}

298 \text{ K}

0.2905

, then the value of equilibrium constant for the cell reaction is : (1)

e^{0.32/0.0295}

(2)

10^{0.32/0.0295}

(3)

10^{0.26/0.0295}

(4)

10^{0.32/0.0591}