The position vector of a point of application of a force is and the force is

PHYSICS · Single correct · CBSE · Physics · System of Particles and Rotational Motion · System of Particles and Rotational Motion

Problem

The position vector of a point of application of a force is

\mathbf{r}=2\,\mathbf{i}+3\,\mathbf{j}-\mathbf{k}\,\text{m}

and the force is

\mathbf{F}=5\,\mathbf{i}-4\,\mathbf{j}+2\,\mathbf{k}\,\text{N}

. The torque about the origin (in N m) is (a)

-2\,\mathbf i+9\,\mathbf j+23\,\mathbf k

(b)

2\,\mathbf i-9\,\mathbf j-23\,\mathbf k

(c)

2\,\mathbf i+9\,\mathbf j-23\,\mathbf k

(d)

2\,\mathbf i-9\,\mathbf j+23\,\mathbf k