At a height of above the ground

PHYSICS · Subjective · CBSE · Physics · Motion in a Plane · Motion in a Plane

Problem

At a height of

45\,\text{m}

above the ground, the velocity of a projectile is

\mathbf{v}=(30\hat{\imath}+40\hat{\jmath})\,\text{m s}^{-1}.

Find the initial velocity, time of flight, maximum height, and horizontal range. Here

\hat{\imath}

and

\hat{\jmath}

are unit vectors in the horizontal and vertical directions. Take

g=10\,\text{m s}^{-2}