A rigid container of volume holds a mixture of two ideal gases that do not react with…

CHEMISTRY · Multi-part · AP · Chemistry · Properties of Substances and Mixtures · Properties of Substances and Mixtures

Problem

A rigid container of volume VV holds a mixture of two ideal gases that do not react with each other. Species A has mass m1m_1, number density n1n_1, and root-mean-square speed vrms,1v_{\text{rms},1}. Species B has mass m2m_2, number density n2n_2, and root-mean-square speed vrms,2v_{\text{rms},2}. Interactions between the two species can be neglected except for perfectly elastic collisions. (a) For species A alone, derive an expression for the partial pressure P1P_1 it exerts on the container walls in terms of n1n_1, m1m_1, and vrms,1v_{\text{rms},1}. (b) Repeat part (a) for species B to obtain its partial pressure P2P_2. (c) Using kinetic arguments, explain why the total pressure PtotP_{\text{tot}} exerted by the mixture equals the sum of the two partial pressures even though atoms of different masses collide with the same walls. (d) Combine your results to write PtotP_{\text{tot}} explicitly in terms of n1n_1, n2n_2, m1m_1, m2m_2, vrms,1v_{\text{rms},1}, and vrms,2v_{\text{rms},2}. Comment on how increasing the heavier species’ number density affects the total pressure when all other quantities remain the same.

Related theory

Browse the problem library