Determine the equation of the tangent line to the curve at .

MATHEMATICS · Single correct · A Level · Mathematics · Differentiation · Differentiation

Problem

Determine the equation of the tangent line to the curve y=sin⁡xy=\sin x at x=π/6x=\pi/6. (a) y−12=12(x−π6)y-\dfrac12 = \dfrac12\left(x-\dfrac{\pi}{6}\right) (b) y−12=−32(x−π6)y-\dfrac12 = -\dfrac{\sqrt3}{2}\left(x-\dfrac{\pi}{6}\right) (c) y−12=32(x−π6)y-\dfrac12 = \dfrac{\sqrt3}{2}\left(x-\dfrac{\pi}{6}\right) (d) y−32=12(x−π6)y-\dfrac{\sqrt3}{2} = \dfrac12\left(x-\dfrac{\pi}{6}\right)

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