CBSE

MATHEMATICS · Single correct · CBSE · Mathematics · Continuity and Differentiability · Continuity and Differentiability

Problem

If x=3at1+t3,y=3at21+t3x = \frac{3at}{1+t^3}, y = \frac{3at^2}{1+t^3} , then dydx=\frac{dy}{dx} = (a) t(2+t3)1−2t3\frac{t(2+t^3)}{1-2t^3} (b) t(2−t3)1−2t3\frac{t(2-t^3)}{1-2t^3} (c) t(2+t3)1+2t3\frac{t(2+t^3)}{1+2t^3} (d) t(2−t3)1+2t3\frac{t(2-t^3)}{1+2t^3}

Related theory

Browse the problem library