The Maclaurin series for is x = _ n=0 ^ (-1)^ n x^ 2n+1 (2n+1)!

MATHEMATICS · Multi-part · AP · Calculus BC · Infinite Sequences and Series · Infinite Sequences and Series

Problem

The Maclaurin series for sin⁡x\sin x is sin⁡x=∑n=0∞(−1)nx2n+1(2n+1)!.\sin x = \sum_{n=0}^{\infty} \frac{(-1)^{n}x^{2n+1}}{(2n+1)!}. Consider the function p(x)=sin⁡(x2)p(x)=\sin(x^{2}). (a) Obtain a power series representation for p(x)p(x) centered at x=0x=0 by making an appropriate substitution in the series above. (b) Using your series, determine the exact value of p(18)(0)p^{(18)}(0). (c) State the radius of convergence of the series for p(x)p(x) and justify your answer.

Related theory

Browse the problem library