A parallel-plate capacitor has plates of area and separation and is charged to a…
PHYSICS · Multi-part · CBSE · Physics · Electrostatic Potential and Capacitance · Electrostatic Potential and Capacitance
Problem
A parallel-plate capacitor has plates of area A and separation d and is charged to a potential difference V. The charging battery is then disconnected, and the plates are pulled apart until their separation is 2d. Derive expressions in terms of A, d, and V for:
(a) The new potential difference
(b) The initial and final stored energies, Ui and Uf
(c) The work required to increase the separation of the plates from d to 2d