In a laboratory, two point masses are placed 0.15m apart in vacuum. One of the masses is 0.25kg. The attractive force measured between them is 9.8×10−6N.
(i) Calculate the mass of the other body.
(ii) Express the measured force in dyne.
(iii) If both masses are doubled simultaneously while the separation remains 0.15m, determine the new force in SI units.