What is the E.M.F

CHEMISTRY · Single correct · A Level · Chemistry · Electrode potentials · Electrode potentials

Problem

What is the E.M.F. of the cell, given EA/A+∘=0.35 VE^{\circ}_{\text{A}/\text{A}^+} = 0.35\,\text{V} and EB/B+∘=−0.42 VE^{\circ}_{\text{B}/\text{B}^+} = -0.42\,\text{V}? The cell has the electrodes A and B in their respective electrolytes. (a) +0.07 V+0.07\,\text{V} (b) −0.07 V-0.07\,\text{V} (c) +0.77 V+0.77\,\text{V} (d) −0.77 V-0.77\,\text{V}

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