An ideal gas is transformed from state to state at constant temperature by the…

PHYSICS · Single correct · AP · Physics 2: Algebra-based · Thermodynamics · Thermodynamics

Problem

An ideal gas is transformed from state A (PA=3.0 atm, VA=2.0 L)A\,(P_A = 3.0\,\text{atm},\, V_A = 2.0\,\text{L}) to state B (PB=1.0 atm, VB=6.0 L)B\,(P_B = 1.0\,\text{atm},\, V_B = 6.0\,\text{L}) at constant temperature by the following quasi-static paths: Path 1: isobaric expansion at 3.0 atm3.0\,\text{atm} from 2.0 L2.0\,\text{L} to 6.0 L6.0\,\text{L}. Path 2: isochoric pressure drop from 3.0 atm3.0\,\text{atm} to 1.0 atm1.0\,\text{atm} at 2.0 L2.0\,\text{L}, then isobaric expansion at 1.0 atm1.0\,\text{atm} from 2.0 L2.0\,\text{L} to 6.0 L6.0\,\text{L}. Path 3: direct isothermal path joining AA and BB. Which option gives the correct order of the magnitude of work done by the gas along the three paths? (a) W3>W1>W2W_3 > W_1 > W_2 (b) W1>W3>W2W_1 > W_3 > W_2 (c) W2>W3>W1W_2 > W_3 > W_1 (d) W1=W2=W3W_1 = W_2 = W_3

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