Consider the differential equation dxdy=x+yy .
(1) Find and simplify an expression for dx2d2y in terms of x and y .
(2) Show that the substitution y=xv transforms this equation into xdxdv=f(v) , where f(v) is a function to be found.
(3) Hence find the particular solution of the equation dxdy=x+yy for which y=1 when x=1 . Give your answer in the form x=g(y) .