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Take Earth’s radius and surface acceleration due to gravity
PHYSICS · Single correct · CBSE · Physics · Gravitation · Gravitation
Problem
Take Earth’s radius
R
=
6.4
×
10
6
m
R = 6.4\times10^{6}\,\text{m}
R
=
6.4
×
1
0
6
m
and surface acceleration due to gravity
g
=
9.8
m s
−
2
g = 9.8\,\text{m s}^{-2}
g
=
9.8
m s
−
2
. Calculate
g
′
g'
g
′
at an altitude of
5
km
5\,\text{km}
5
km
above the surface (
h
≪
R
h \ll R
h
≪
R
). (a)
9.82
m s
−
2
9.82\,\text{m s}^{-2}
9.82
m s
−
2
(b)
9.78
m s
−
2
9.78\,\text{m s}^{-2}
9.78
m s
−
2
(c)
9.65
m s
−
2
9.65\,\text{m s}^{-2}
9.65
m s
−
2
(d)
9.79
m s
−
2
9.79\,\text{m s}^{-2}
9.79
m s
−
2
Related theory
Variation of g
Gravitational Field & Acceleration
Gravitation
Acceleration due to gravity above and below Earth's surface
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