CBSE

MATHEMATICS · Single correct · CBSE · Mathematics · Inverse Trigonometric Functions · Inverse Trigonometric Functions

Problem

If x=tan⁡−11−cos⁡−1(−12)+sin⁡−112x = \tan^{-1}1 - \cos^{-1}\left(-\frac{1}{2}\right) + \sin^{-1}\frac{1}{2} ; y=cos⁡(12cos⁡−1(18))y = \cos\left(\frac{1}{2}\cos^{-1}\left(\frac{1}{8}\right)\right) , then (1) x=πyx = \pi y (2) y=πxy = \pi x (3) tan⁡x=−(4/3)y\tan x = -(4/3)y (4) tan⁡x=(4/3)y\tan x = (4/3)y

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