Define the function by h(x)= cases x^2-4, & x 2

MATHEMATICS · Multi-part · AP · Calculus AB · Limits and Continuity · Limits and Continuity

Problem

Define the function hh by h(x)={x2−4,x≤2,k−x,x>2,h(x)=\begin{cases} x^2-4, & x\le 2,\\ k - x, & x>2, \end{cases} where kk is a constant. (a) Determine the value of kk that makes hh continuous at x=2x=2. (b) Using your value of kk, evaluate h(−3)h(-3) and h(6)h(6). Explain why the equation h(x)=0h(x)=0 must have at least one real solution on (−3,6)(-3,6). (c) Identify two consecutive integers between which a solution to h(x)=0h(x)=0 is guaranteed to lie, and justify your choice.

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