Define by h(x)= cases x+1,&x<0 x^ 2 +k,&x 0 cases

MATHEMATICS · Single correct · AP · AP Precalculus · Exponential and Logarithmic Functions · Exponential and Logarithmic Functions

Problem

Define h:R→Rh:\mathbb R\to\mathbb R by h(x)={x+1,x<0x2+k,x≥0.h(x)=\begin{cases}x+1,&x<0\\ x^{2}+k,&x\ge 0\end{cases}. For which real values of kk is hh one-to-one on R\mathbb R? (a) k<1k<1 (b) k=1k=1 (c) k≥1k\ge 1 (d) All real kk

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