Which expression correctly gives the work done by a constant force acting parallel to…

PHYSICS · Single correct · CBSE · Physics · Work and Energy · Work and Energy

Problem

Which expression correctly gives the work WW done by a constant force F⃗\vec F acting parallel to the displacement s⃗\vec s? (a) W=12FsW = \dfrac{1}{2}Fs (b) W=Fssin⁡θW = Fs\sin \theta (c) W=Fscos⁡180∘W = Fs\cos 180^{\circ} (d) W=FsW = Fs

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