Between and seconds

MATHEMATICS · Single correct · AP · Calculus AB · Applications of Integration · Applications of Integration

Problem

Between t=0t=0 and t=9t=9 seconds, the velocity v(t)v(t) of a particle satisfies v(t)≥0v(t)\ge 0 on [0,4][0,4] and v(t)≤0v(t)\le 0 on (4,9](4,9]. The region above the tt-axis and below the graph of vv on [0,4][0,4] has area 1515 (meter-seconds). The region below the tt-axis and above the graph of vv on [4,9][4,9] has area 66 (meter-seconds). What is ∫09∣v(t)∣ dt∫09v(t) dt\displaystyle \frac{\int_{0}^{9} |v(t)|\,dt}{\int_{0}^{9} v(t)\,dt}? (a) 156\dfrac{15}{6} (b) 1 (c) 73\dfrac{7}{3} (d) 53\dfrac{5}{3}

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