A function is defined for all by p(x)= ( 1 x-2 ) x-2 +4

MATHEMATICS · Multi-part · AP · Calculus AB · Limits and Continuity · Limits and Continuity

Problem

A function pp is defined for all x≠2x\ne 2 by p(x)=sin⁡(1x−2)x−2+4.p(x)=\frac{\sin\left(\tfrac{1}{x-2}\right)}{x-2}+4. When graphed on a calculator in the window −5≤x≤5-5 \le x \le 5 and 0≤y≤80 \le y \le 8, pp appears to approach the horizontal line y=4y=4 as xx approaches 22. Analyze the behavior of pp near x=2x=2 and decide whether lim⁡x→2p(x)\displaystyle \lim_{x\to 2} p(x) exists. (a) Using the definition of pp, rewrite p(x)−4p(x)-4 as a product of two factors. State the two factors explicitly. (b) Explain why one of the factors identified in part (a) becomes unbounded as x→2x\to 2 while the other remains bounded. Support your explanation with appropriate limit properties or theorems. (c) Prove that lim⁡x→2p(x)\displaystyle \lim_{x\to 2} p(x) does not exist, even though the calculator graph in the given window suggests convergence to 44. (d) Discuss how successively smaller xx–intervals centered at x=2x=2 would change the visual appearance of the graph and what a student should look for to avoid an incorrect conclusion about the limit.

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