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MATHEMATICS · Single correct · AP · AP Precalculus · Exponential and Logarithmic Functions · Exponential and Logarithmic Functions

Problem

The solution of 42x−6(4)x+8=04^{2x} - 6(4)^x + 8 = 0 is: (A) x=12x = \frac{1}{2} (B) x=1x = 1 (C) x=12,1x = \frac{1}{2}, 1 (D) x=−12,3x = -\frac{1}{2}, 3

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