CHEMISTRY · Multi-part · A Level · Chemistry · Chemical equilibria (Le Chatelier’s principle and Kc) · Chemical equilibria (Le Chatelier’s principle and Kc)
Problem
The water–gas shift reaction
CO(g)+H2O(g)⇌CO2(g)+H2(g)Kc=10.3 (at 700K, forward reaction endothermic)
occurs in a rigid vessel. The mixture is first brought to equilibrium at 700K with the following concentrations:
[CO]=0.40M, [H2O]=0.40M, [CO2]=0.20M, [H2]=0.20M.
A sequence of three stresses is then applied while the temperature or volume is varied as indicated. Concentrations are recorded continuously.
• t1=0min Volume is halved instantaneously (from 2.00L to 1.00L) at constant temperature.
• t2=8min After the system has re-established equilibrium, 0.050mol of CO2 is removed rapidly; T and V remain constant.
• t4=22min Immediately after the second re-equilibration, the temperature is raised to 750K; the new equilibrium constant is Kc′=14.7.
Answer the following questions about the system’s behavior. (Assume ideal gases throughout.)
(a) Immediately after the volume is halved at t1, calculate the reaction quotient Qc using the instantaneous concentrations that result solely from the volume change. Show numerically that the system is no longer at equilibrium.
(b) Using the Qc value from part (a), determine the direction of the net reaction between t1 and t2. Explain your reasoning with reference to Qc and Kc.
(c) Just after the removal of CO2 at t2, calculate the new Qc and predict the direction in which the system will shift between t2 and the next equilibrium point at t3.
(d) Explain qualitatively how the temperature increase at t4 (700K→750K) affects the relative concentrations of reactants and products once the system reaches the new equilibrium, taking into account both the magnitude of Kc and the stated thermochemistry of the reaction.