The yearly profit (in thousand rupees) of a stationery company from selling thousand…

MATHEMATICS · Multi-part · CBSE · Mathematics · Polynomials · Polynomials

Problem

The yearly profit (in thousand rupees) of a stationery company from selling nn thousand notebooks is modelled by the polynomial P(n)=−2n2+50n−200P(n)=-2n^{2}+50n-200. A rival company’s yearly profit (in thousand rupees) from the same market is given by Q(n)=−n2+40n−150Q(n)=-n^{2}+40n-150. (i) Find the polynomial D(n)=P(n)−Q(n)D(n)=P(n)-Q(n) representing how much more profit (in thousand rupees) the stationery company makes than its rival. (ii) Calculate this profit difference when n=20n=20. (iii) Interpret the sign of each coefficient in D(n)D(n) with respect to how the difference in profits changes as the number of notebooks sold increases.

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