Area of quadrilateral formed with the foci of the hyperbola and is

MATHEMATICS · Single correct · AP · AP Precalculus · Functions with Parameters, Vectors, and Matrices · Functions with Parameters, Vectors, and Matrices

Problem

Area of quadrilateral formed with the foci of the hyperbola x2a2−y2b2=1\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 and x2a2−y2b2=−1\frac{x^2}{a^2} - \frac{y^2}{b^2} = -1 is (1) 4(a2+b2)4(a^2 + b^2) (2) 2(a2+b2)2(a^2 + b^2) (3) (a2+b2)(a^2 + b^2) (4) 12(a2+b2)\frac{1}{2}(a^2 + b^2)

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