Kerosene flows upward through a vertical pipe

PHYSICS · Single correct · AP · Physics 1: Algebra-based · Fluids · Fluids

Problem

Kerosene (ρ=800 kg m−3)(\rho = 800\,\text{kg m}^{-3}) flows upward through a vertical pipe. At point AA the speed is 1.5 m s−11.5\,\text{m s}^{-1} and the gauge pressure is 3.0×104 Pa3.0\times10^{4}\,\text{Pa}. Point BB is 2.0 m2.0\,\text{m} higher and the speed there is 2.5 m s−12.5\,\text{m s}^{-1}. Take g=9.8 m s−2g = 9.8\,\text{m s}^{-2}. What is the gauge pressure at BB? (a) 2.8×104 Pa2.8 \times 10^{4}\,\text{Pa} (b) 4.4×104 Pa4.4 \times 10^{4}\,\text{Pa} (c) 1.3×104 Pa1.3 \times 10^{4}\,\text{Pa} (d) 0.84×104 Pa0.84 \times 10^{4}\,\text{Pa}

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