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Chords and of a circle are equidistant from the centre O
MATHEMATICS · Single correct · CBSE · Mathematics · Circles · Circles
Problem
Chords
A
B
AB
A
B
and
C
D
CD
C
D
of a circle are equidistant from the centre O. If
∠
A
O
B
=
(
4
x
−
10
)
∘
\angle AOB = (4x - 10)^{\circ}
∠
A
O
B
=
(
4
x
−
10
)
∘
and
∠
C
O
D
=
(
2
x
+
50
)
∘
\angle COD = (2x + 50)^{\circ}
∠
C
O
D
=
(
2
x
+
50
)
∘
, then the measure of
∠
A
O
B
\angle AOB
∠
A
O
B
is (a)
120
∘
120^{\circ}
12
0
∘
(b)
110
∘
110^{\circ}
11
0
∘
(c)
100
∘
100^{\circ}
10
0
∘
(d)
80
∘
80^{\circ}
8
0
∘
Related theory
Chord Properties
Circles
Equal chords and their distances
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