| Column I | Column II | |---|---| | A

MATHEMATICS · Subjective · CBSE · Mathematics · Three-Dimensional Geometry · Three-Dimensional Geometry

Problem

\frac{x-2}{3} = \frac{y-3}{4} = \frac{z-4}{5}

Column I	Column II
A. Point on the line at a distance $10\sqrt{2}$ from $(2, 3, 4)$	p. $(-1, -1, -1)$
B. Point on the line common to the plane $x + y + z + 3 = 0$	q. $(2, 3, 4)$
C. Point on the line at a distance $\sqrt{29}$ from the origin.	r. $(8, 11, 14)$
D. Point on the line common to the plane $x + y - z + 3 = 0$	s. $(-4, -5, -6)$