Table 1 shows the values of a twice–differentiable function together with two…

MATHEMATICS · Multi-part · AP · Calculus BC · Infinite Sequences and Series · Infinite Sequences and Series

Problem

Table 1 shows the values of a twice–differentiable function gg together with two different polynomial approximations, P2P_2 and P4P_4, for several values of xx near 0. Table 1 (all values rounded to 6 decimal places) xx   |  g(x)g(x)   |  P2(x)=x−x22P_2(x)=x-\tfrac{x^2}{2}  |  P4(x)=x−x22+x33−x44P_4(x)=x-\tfrac{x^2}{2}+\tfrac{x^3}{3}-\tfrac{x^4}{4} ─────┼─────────────────┼──────────────────────────────┼────────────────────────────────────────── 0.1 | 0.095310 | 0.095000 | 0.095308 0.3 | 0.262364 | 0.255000 | 0.261554 0.5 | 0.405465 | 0.375000 | 0.401042 (The actual function is g(x)=ln⁡(1+x)g(x)=\ln(1+x), but this need not be used explicitly.) (1) Part 1: (a) Discuss how the numerical data in Table 1 illustrate the relative accuracy of P2P_2 and P4P_4 for estimating g(x)g(x) when xx is close to 0. (2) Part 2: (b) Provide a mathematical explanation, based on the way P2P_2 and P4P_4 are constructed, for why P4P_4 generally gives a smaller error than P2P_2 when ∣x∣|x| is small. (3) Part 3: (c) Without performing any additional computation, predict which polynomial—P2P_2 or P4P_4—will give the more accurate estimate of g(0.8)g(0.8). Justify your answer in terms of the structure of the two polynomials and their agreement with gg at x=0x=0.

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