A sample of gaseous HCl is examined at two temperatures

CHEMISTRY · Single correct · A Level · Chemistry · Bonding · Bonding

Problem

A sample of gaseous HCl is examined at two temperatures, 200 K200\,\text{K} and 800 K800\,\text{K}, at constant density. Which statement describes how the relative importance of dipole–dipole interactions compared with London dispersion forces changes as the temperature increases from 200 K200\,\text{K} to 800 K800\,\text{K}? (a) Both interactions increase equally with temperature, so their relative importance is unchanged. (b) London dispersion forces become negligible at 800 K800\,\text{K} because the thermal motion prevents formation of instantaneous dipoles. (c) Dipole–dipole interactions become relatively less important because rapid molecular rotation at 800 K800\,\text{K} averages the orientation of dipoles, whereas London dispersion forces are unaffected by rotation. (d) Dipole–dipole interactions become relatively more important because higher kinetic energy helps the dipoles align during collisions, while London dispersion forces remain constant.

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