A particle moves along a parametric curve with position functions and

MATHEMATICS · Single correct · AP · Calculus BC · Parametric, Polar, and Vector-Valued Functions · Parametric, Polar, and Vector-Valued Functions

Problem

A particle moves along a parametric curve with position functions x(t)x(t) and y(t)y(t). Its speed is constant and non-zero for all t≥0t\ge 0. Which statement best explains why solving the equation s(t)=12s(T)s(t)=\tfrac12 s(T) yields the time when the particle has traveled half the total distance covered by time TT? (a) Because the particle moves in a straight line, the displacement equals the arc length, so setting the xx-coordinate equal to half its final value finds the time. (b) Because the particle’s speed is constant, but the distance is obtained by integrating the speed once more, s(t)=12vt2s(t)=\tfrac12 v t^{2}; therefore halving the distance corresponds to t=T/2t=T/\sqrt{2}. (c) Because the integrand in the arc-length integral is constant, the accumulated length is proportional to tt, so equating half the total length directly gives the corresponding time. (d) Because the parameter tt itself always measures distance traveled, the condition s(t)=12s(T)s(t)=\tfrac12 s(T) is automatically satisfied at t=T/2t=T/2 regardless of speed.

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