The position of a particle is

MATHEMATICS · Single correct · AP · Calculus BC · Parametric, Polar, and Vector-Valued Functions · Parametric, Polar, and Vector-Valued Functions

Problem

The position of a particle is r(t)=⟨t3, 3t2−6t, 4⟩\mathbf r(t)=\langle t^{3},\, 3t^{2}-6t,\,4\rangle. For what value of tt in the interval 0≤t≤20\le t\le 2 are the velocity and acceleration vectors perpendicular? (a) t=1t=1 (b) t≈0.77  (the real root of t3+2t−2=0)t\approx0.77\;(\text{the real root of }t^{3}+2t-2=0) (c) t=23t=\sqrt{\dfrac{2}{3}} (d) There is no such tt in the interval.

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