If the straight lines and x+1 5 = y+1 2 = z k are coplanar

MATHEMATICS · Single correct · ISC · Mathematics · Three-Dimensional Geometry · Three-Dimensional Geometry

Problem

If the straight lines x−12=y+1k=z2\frac{x-1}{2} = \frac{y+1}{k} = \frac{z}{2} and x+15=y+12=zk\frac{x+1}{5} = \frac{y+1}{2} = \frac{z}{k} are coplanar, then the plane(s) containing these two lines is/are (1) y+2z=−1y + 2z = -1 (2) y+z=−1y + z = -1 (3) y−z=−1y - z = -1 (4) y−2z=−1y - 2z = -1

Related theory

Browse the problem library