A proton ( , ) enters a uniform magnetic field with speed

PHYSICS · Single correct · AP · Physics 2: Algebra-based · Magnetism and Electromagnetism · Magnetism and Electromagnetism

Problem

A proton (m=1.67×10−27 kgm=1.67\times10^{-27}\,\text{kg}, q=1.6×10−19 Cq=1.6\times10^{-19}\,\text{C}) enters a 0.10 T0.10\,\text{T} uniform magnetic field with speed 2.0×106 m s−12.0\times10^{6}\,\text{m s}^{-1}, making an angle of 45∘45^{\circ} with the field direction. The radius of the circular component of its path is closest to (a) 0.30 m0.30\,\text{m} (b) 0.15 m0.15\,\text{m} (c) 0.11 m0.11\,\text{m} (d) 0.21 m0.21\,\text{m}

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