For the curve

MATHEMATICS · Single correct · CBSE · Mathematics · Continuity and Differentiability · Continuity and Differentiability

Problem

For the curve xsin⁡y+ycos⁡x=1x\sin y + y\cos x = 1, determine dydx\dfrac{dy}{dx}. (a) ysin⁡x−sin⁡yxcos⁡y−cos⁡x\dfrac{y \sin x - \sin y}{x \cos y - \cos x} (b) ysin⁡x−sin⁡yxcos⁡y+cos⁡x\dfrac{y \sin x - \sin y}{x \cos y + \cos x} (c) sin⁡y−ysin⁡xxcos⁡y+cos⁡x\dfrac{\sin y - y \sin x}{x \cos y + \cos x} (d) ysin⁡x−sin⁡yxcos⁡y\dfrac{y \sin x - \sin y}{x \cos y}

Related theory

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