A torsion spring inside a mechanical watch applies a torque on the balance wheel that…

PHYSICS · Multi-part · CBSE · Physics · System of Particles and Rotational Motion · System of Particles and Rotational Motion

Problem

A torsion spring inside a mechanical watch applies a torque on the balance wheel that varies with angular position according to τ(θ)=τmax⁡sin⁡(2θ)\tau(\theta) = \tau_{\max}\sin(2\theta), where τmax⁡=1.2×10−3 N⋅m\tau_{\max} = 1.2\times10^{-3}\,\text{N}\cdot\text{m}. The balance wheel is displaced from its equilibrium position (θ=0\theta = 0) to θ=π/4 rad\theta = \pi/4\,\text{rad} and then released. (a) Derive an expression for the work done on the balance wheel by the torsion spring as the wheel is displaced from θ=0\theta = 0 to an arbitrary angle θ\theta. (b) Determine the numerical value of the work stored in the spring when the wheel reaches θ=π/4 rad\theta = \pi/4\,\text{rad}. (c) The average torque during the displacement can be defined as τavg=workangular displacement\tau_{\text{avg}} = \frac{\text{work}}{\text{angular displacement}}. Calculate τavg\tau_{\text{avg}} for the motion described and compare it to τmax⁡\tau_{\max}. Explain why τavg\tau_{\text{avg}} is smaller than τmax⁡\tau_{\max}. (d) If friction inside the watch removes 3.0×10−4 J3.0\times10^{-4}\,\text{J} of energy each oscillation, determine whether the energy stored at θ=π/4 rad\theta = \pi/4\,\text{rad} is sufficient for the balance wheel to return to its equilibrium position on the first swing. Justify your answer quantitatively.

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